by amm in ny
On some forum or other, I read that the maximum throughput (in, say, trains per hour or passengers per hour) was reached at something like 40 miles per hour. That is, as you raise the speed of the trains, at some point, you reduce the maximum number of passengers that can be carried per hour from point A to point B on a track, and that this point is reached way below any speed that most of us would call "high speed rail." In other words, HSR is a less efficient (in terms of throughput) use of tracks than lower-speed trains.
I was surprised at this, so I put together a rather simple-minded mathematical model.
First:
Capacity = (Passengers per unit time) = N v / s
where
N = passengers per train
v = speed
s = train spacing.
Next, I assumed that trains have to have at least one braking distance between them. That is, the spacing has to be such that if the train in front of you were stopped (or were to stop instantly), you could come to a complete stop without hitting it. That gives:
s = L + (v^2)/(2 B)
where
L = the amount of track space a train takes up when stopped (that's bigger than the actual train lenght, BTW)
B = the maximum braking deceleration that it is safe to assume you have.
and get:
capacity = N v / ( L + (v^2)/(2 B) )
A little calculus shows that this is maximized when
L = (v^2)/(2 B)
That is, the maximum transport is reached when your braking distance is equal to the space that a train occupies when stopped (or is very slow.)
My first reaction was that this must be a very slow speed. I realize that I have no idea what numbers to use for L or B, but I have a really hard time believing that a 40 mph train can stop in, say, 8 car lengths.
Does my analysis make sense? Is my model at all reasonable?
And does anyone have a better idea what stopping lengths are for trains, or how much space railroads have to give to a typical passenger train before allowing for the increased stopping distance due to speed?
I was surprised at this, so I put together a rather simple-minded mathematical model.
First:
Capacity = (Passengers per unit time) = N v / s
where
N = passengers per train
v = speed
s = train spacing.
Next, I assumed that trains have to have at least one braking distance between them. That is, the spacing has to be such that if the train in front of you were stopped (or were to stop instantly), you could come to a complete stop without hitting it. That gives:
s = L + (v^2)/(2 B)
where
L = the amount of track space a train takes up when stopped (that's bigger than the actual train lenght, BTW)
B = the maximum braking deceleration that it is safe to assume you have.
and get:
capacity = N v / ( L + (v^2)/(2 B) )
A little calculus shows that this is maximized when
L = (v^2)/(2 B)
That is, the maximum transport is reached when your braking distance is equal to the space that a train occupies when stopped (or is very slow.)
My first reaction was that this must be a very slow speed. I realize that I have no idea what numbers to use for L or B, but I have a really hard time believing that a 40 mph train can stop in, say, 8 car lengths.
Does my analysis make sense? Is my model at all reasonable?
And does anyone have a better idea what stopping lengths are for trains, or how much space railroads have to give to a typical passenger train before allowing for the increased stopping distance due to speed?