• Lake Shore Limited

  • Discussion related to Amtrak also known as the National Railroad Passenger Corp.
Discussion related to Amtrak also known as the National Railroad Passenger Corp.

Moderators: GirlOnTheTrain, mtuandrew, Tadman

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  by Backshophoss
 
What would help 448/449 is CSX's constant interference of killing the Boston section for trackwork on a regular basis.
The MBTA PTC install is a one time "Hit" as was the "Destress" trackwork to get rid of the heat restrictions in MBTA territory.
  by charlesriverbranch
 
I'm looking at #49 at Elkhart on Virtual Railfan right now. There is a baggage car between the two New York sleepers. I don't think I've ever seen that done before.
  by dgvrengineer
 
The New York section has been cut back to one sleeper since it went to 3 times per week. The sleeper on the rear was a deadhead car.
  by charlesriverbranch
 
Huh? Shouldn't a train that runs less than half as frequently have more cars, not fewer? What about using the extra cars to encourage social distancing?
  by Amtrak706
 
charlesriverbranch wrote: Sun Oct 18, 2020 5:49 am Huh? Shouldn't a train that runs less than half as frequently have more cars, not fewer? What about using the extra cars to encourage social distancing?
Common sense would say so, yes. So it makes sense then that Amtrak is doing the opposite...
  by electricron
 
charlesriverbranch wrote: Sun Oct 18, 2020 5:49 am Huh? Shouldn't a train that runs less than half as frequently have more cars, not fewer? What about using the extra cars to encourage social distancing?
Yes, that would be true if ridership remains the same. But it is not the same, ridership is down 80% nationally, although individual long distance trains may vary.
Some math exercises of what ifs....
100% x 7 days a week = 700% total ridership.
700% ridership / 3 trains per week = 233% ridership per train.
To serve 233% riders per train, the train would need to be at least twice as long.

20% x 7 trains a week = 140% total ridership
140% ridership / 3 trains per week = 47% ridership per train
To serve 47% riders per train, the train could be at most half as long.

Granted, that math exercise reflects 80% drop in ridership, I have no idea what the real percentages are. But this exercise in what ifs show what Amtrak is faced with. And why a train half as long half the time can meet the present decrease of customer demands in ridership.

Math is the basic ingredient of every successful business in the entire world. That is why it is taught in schools all over the world. Math does not lie.
  by WashingtonPark
 
Except Amtrak brags about social distancing, so to maintain 50% distance the trains would have to be as long at 3 times per week as they were at 7. Of course this would be coach seating. Wouldn't apply to the sleepers that could be cut in half.
  by electricron
 
WashingtonPark wrote: Sun Oct 18, 2020 12:25 pm Except Amtrak brags about social distancing, so to maintain 50% distance the trains would have to be as long at 3 times per week as they were at 7. Of course this would be coach seating. Wouldn't apply to the sleepers that could be cut in half.
Again, that is assuming the same amount of ridership. Ridership is down 80% nationally, that is one-fifth less ridership than before. That means it takes Amtrak 5 days to have as much ridership as they had in one day pre-covid.
  by WashingtonPark
 
electricron wrote: Sun Oct 18, 2020 3:36 pm
WashingtonPark wrote: Sun Oct 18, 2020 12:25 pm Except Amtrak brags about social distancing, so to maintain 50% distance the trains would have to be as long at 3 times per week as they were at 7. Of course this would be coach seating. Wouldn't apply to the sleepers that could be cut in half.
Again, that is assuming the same amount of ridership. Ridership is down 80% nationally, that is one-fifth less ridership than before. That means it takes Amtrak 5 days to have as much ridership as they had in one day pre-covid.
Which would be 2 1/3 days if you want to keep the train half full. Which means you would have to maintain the same number of coaches on a three day schedule to maintain social distancing in a car you are only going to allow to be filled at 50%. (Say 1400 per 7 days. 200 a day. 50 seats a car means 4 cars. Now 20% of 1400 is 280 for 3 trains is 93 per train. Want to do social distancing at 50%? 25 per car so you still need 4 cars. Only sleeper cars could be cut under the present ridership.)
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